Answer
49
Work Step by Step
We will use the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$ in the simplification of the expression:
$\frac{7^{\frac{4}{3}}}{7^{-\frac{2}{3}}}=7^{\frac{4}{3}-(-\frac{2}{3})}=7^{\frac{4}{3}+\frac{2}{3}}=7^{\frac{4+2}{3}}=7^{\frac{6}{3}}=7^{2}=49$
