Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3 - Page 489: 49



Work Step by Step

We will use the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$ in the simplification of the expression: $\frac{7^{\frac{4}{3}}}{7^{-\frac{2}{3}}}=7^{\frac{4}{3}-(-\frac{2}{3})}=7^{\frac{4}{3}+\frac{2}{3}}=7^{\frac{4+2}{3}}=7^{\frac{6}{3}}=7^{2}=49$
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