Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3 - Page 489: 47

Answer

4

Work Step by Step

We will use the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$ in the simplification of the expression: $\frac{2^{\frac{9}{4}}}{2^{\frac{1}{4}}}=2^{\frac{9}{4}-\frac{1}{4}}=2^{\frac{9-1}{4}}=2^{\frac{8}{4}}=2^{2}=4$
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