Answer
$2x^{2}y$
Work Step by Step
Raising each term in the expression to the power of $1/3$ and then simplifying, we obtain:
$(8x^{6}y^{3})^{\frac{1}{3}}$
=$(8)^{\frac{1}{3}}(x^{6})^{\frac{1}{3}}(y^{3})^{\frac{1}{3}}$
=$(2^{3})^{\frac{1}{3}}(x^{6\times\frac{1}{3}})y^{3\times\frac{1}{3}}$
=$2^{1}(x^{2})(y)^{1}$
=$2x^{2}y$
