Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.3 - Fractional Exponents - Problem Set 11.3 - Page 489: 36



Work Step by Step

Remember that whenever a fraction is raised to a negative power, we flip the numerator and the denominator of the fraction and make the exponent positive. Thus, we find: $(1/27)^{-2/3} = (27^{2/3})$ Now, recall the formula:$ a^{b/c}=( \sqrt[c] {a})^{b}$. Thus, we obtain: $(27^{2/3})=(\sqrt[3] {27})^{2}=(3^{2})=9$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.