College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 97

Answer

$(3x-1)(x-2)(x+2)$

Work Step by Step

We factor using grouping: $3x^{3}-x^{2}-12x+4=3x^{3}-12x-x^{2}+4=3x(x^{2}-4)-(x^{2}-4)=(3x-1)(x^{2}-4)=(3x-1)(x-2)(x+2)$
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