College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 58

Answer

$\displaystyle \frac{2x+1}{\sqrt{x}\sqrt{x+1}}$

Work Step by Step

We factor out $x^{-1/2}(x+1)^{-1/2}$: $x^{-1/2}(x+1)^{1/2}+x^{1/2}(x+1)^{-1/2}=x^{-1/2}(x+1)^{-1/2}[(x+1)+x]=x^{-1/2}(x+1)^{-1/2}(2x+1)=\displaystyle \frac{2x+1}{\sqrt{x}\sqrt{x+1}}$
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