College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 117

Answer

(a) 1055 (b) 484 (c) 20300

Work Step by Step

We use the formula $a^2-b^2=(a+b)(a-b)$: (a) $528^{2}-527^{2}=(528-527)(528+527)=1(1055)=1055$ (b) $122^{2}-120^{2}=(122-120)(122+120)=2(242)=484$ (c) $1020^{2}-1010^{2}=(1020-1010)(1020+1010)=10(2030)=20300$
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