College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises - Page 43: 100



Work Step by Step

$(1+\displaystyle \frac{1}{x})^{2}-(1-\frac{1}{x})^{2}=[(1+\frac{1}{x})-(1-\frac{1}{x})][(1+\frac{1}{x})+(1-\frac{1}{x})] =(1+\frac{1}{x}-1+\frac{1}{x})(1+\frac{1}{x}+1-\frac{1}{x})=(\frac{2}{x})(2)=\frac{4}{x}$
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