## College Algebra 7th Edition

$(y-3)(y-2)(y+2)$
$y^{3}-3y^{2}-4y+12 =(y^{3}-3y^{2})+(-4y+12)=y^{2}(y-3)+(-4)(y-3)=(y-3)(y^{2}-4)$ Last we use $(a^2-b^2)=(a+b)(a-b)$: $=(y-3)(y-2)(y+2)$