College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises - Page 43: 108



Work Step by Step

Think of the equation as $x^2-2x-3$, with $x=a^2+2a$. We then get: $(a^{2}+2a)^{2}-2(a^{2}+2a)-3=[(a^{2}+2a)-3][(a^{2}+2a)+1]=(a^{2}+2a-3)(a^{2}+2a+1)=(a-1)(a+3)(a+1)^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.