College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises - Page 43: 93

Answer

$(x^{2}-2y)(x^{4}+2x^{2}y+4y^{2})$

Work Step by Step

$x^{6}-8y^{3}=(x^{2})^{3}-(2y)^{3}=(x^{2}-2y)[(x^{2})^{2}+(x^{2})(2y)+(2y)^{2}]=(x^{2}-2y)(x^{4}+2x^{2}y+4y^{2})$
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