## College Algebra 7th Edition

Published by Brooks Cole

# Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 85

#### Answer

$(2x-5)(4x^2+10x+25)$

#### Work Step by Step

RECALL: A difference of two cubes can be factored using the formula $A^3-B^3=(A-B)(A^2+AB+B^2)$ The given binomial can be written as: $=(2x)^3-5^3$ The binomial is a difference of two cubes. Factor using the formula above with $A=2x$ and $B=5$ to obtain: $=(2x-5)[(2x)^2+(2x)(5)+5^2) \\=(2x-5)(4x^2+10x+25)$

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