College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises - Page 43: 107



Work Step by Step

Think of the equation as $x^{2}-7x+10$, with $a^{2}+1$ being $x$. We then get: $(a^{2}+1)^{2}-7(a^{2}+1)+10=[(a^{2}+1)-2][(a^{2}+1)-5]=(a^{2}-1)(a^{2}-4)=(a-1)(a+1)(a-2)(a+2)$
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