## College Algebra 7th Edition

$\frac{1}{3}(x+6)^{-2/3}(2x-3)(14x+69)$
Factor out $x+6$ and $2x-3$: $\displaystyle \frac{1}{3}(x+6)^{-2/3}(2x-3)^{2}+(x+6)^{1/3}(2)(2x-3)(2)=\frac{1}{3}(x+6)^{-2/3}(2x-3)[(2x-3)+(3)(x+6)(4)] =\frac{1}{3}(x+6)^{-2/3}(2x-3)[2x-3+12x+72]=\frac{1}{3}(x+6)^{-2/3}(2x-3)(14x+69)$