College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.6 - Factoring - P.6 Exercises: 60

Answer

$\frac{\sqrt[4]{x^{2}+1}(2x^{2}+3)}{\sqrt{x}}$

Work Step by Step

We factor out common terms and simplify: $3x^{-1/2}(x^{2}+1)^{5/4}-x^{3/2}(x^{2}+1)^{1/4}=x^{-1/2}(x^{2}+1)^{1/4}[3(x^{2}+1)-(1)x^{2}]=x^{-1/2}(x^{2}+1)^{1/4}(3x^{2}+3-x^{2})=x^{-1/2}(x^{2}+1)^{1/4}(2x^{2}+3)=\frac{\sqrt[4]{x^{2}+1}(2x^{2}+3)}{\sqrt{x}}$
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