College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Mid-Chapter Check Point - Page 479: 8


Domain: $(-\infty,-6)\cup(-6,\infty)$.

Work Step by Step

Domain restriction for logarithmic functions: the argument of the logarithm must be positive. $h(x)=\log_{3}(x+6)^{2}$ $(x+6)^{2}>0$ A square of a real number is nonnegative, so the only problem is when the LHS is zero: $x+6=0$ $x=-6\qquad $ ... $-6$ is the only number excluded Domain: $(-\infty,-6)\cup(-6,\infty)$.
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