College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Mid-Chapter Check Point - Page 479: 18

Answer

13

Work Step by Step

Apply the Basic Logarithmic Property: $b^{\log_{b}x}=x$ and the fact that $\log x=\log_{10}x$ (common logarithm has base 10)$:$ $10^{\mathrm{l}\mathrm{o}\mathrm{g}13}=10^{\mathrm{l}\mathrm{o}\mathrm{g}_{10}13}=13$
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