College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Mid-Chapter Check Point - Page 479: 24

Answer

$= \log_5 x^{9}$

Work Step by Step

$= 7\log_5 x + 2\log_5 x$ $= \log_5 x^{7} + \log_5 x^{2}$ $= \log_5 x^{7}x^{2}$ $= \log_5 x^{9}$
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