College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Mid-Chapter Check Point - Page 479: 20

Answer

$\sqrt{\pi}$

Work Step by Step

Apply the Basic Logarithmic Property: $\log_{b}b^{x}=x$ b=$\pi,\ x=\sqrt{\pi},$ $\log_{\pi}\pi^{\sqrt{\pi}}=\sqrt{\pi}$
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