College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Mid-Chapter Check Point - Page 479: 17

Answer

$\sqrt{7}$

Work Step by Step

Apply the Basic Logarithmic Property: $b^{\log_{b}x}=x$ and the fact that $\ln x=\log_{e}x$ (natural logarithm has base e)$:$ $\ln e^{\sqrt{7}}=\log_{e}e^{\sqrt{7}}=\sqrt{7}$
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