Answer
-2
Work Step by Step
We know that $y=log_{b}x$ is equivalent to $b^{y}=x$ (where $x\gt0$, $b\gt0$, and $b\ne1$).
Therefore, $log_{3}\frac{1}{9}=-2$, because $3^{-2}=\frac{1}{3^{2}}=\frac{1}{9}$.
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter 4 - Mid-Chapter Check Point - Page 479: 11
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