College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Mid-Chapter Check Point - Page 479: 19

Answer

$y=-\displaystyle \frac{1}{2}$

Work Step by Step

Definition of the logarithmic function: For $x>0$ and $b>0, b\neq 1,$ $y=\log_{b}x$ is equivalent to $b^{y}=x$. So, $\log_{100}0.1=y$ means that $100^{y}=0.1$ (solve for y) $ 100^{y}=0.1\qquad$ recognize powers of 10 $(10^{2})^{y}=10^{-1}$ $10^{2y}=10^{-1}$ ...if the bases are equal, so must be the exponents 2$y=-1$ $y=-\displaystyle \frac{1}{2}$
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