Answer
no real solution
Work Step by Step
We know that $y=log_{b}x$ is equivalent to $b^{y}=x$ (where $x\gt0$, $b\gt0$, and $b\ne1$).
Therefore, $log_{3}(log_{2}\frac{1}{8})=log_{3}(-3)$, which does not have a solution (as there is no real number $a$ such that $3^{a}=-3$).
