College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Mid-Chapter Check Point - Page 479: 23

Answer

$= \log_7 \frac{x^{8}}{\sqrt[3] y}$

Work Step by Step

$= 8 \log_7 x - \frac{1}{3}\log_7 y$ $= \log_7 x^{8} - \log_7 \sqrt[3] y$ $= \log_7 \frac{x^{8}}{\sqrt[3] y}$
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