College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Mid-Chapter Check Point - Page 479: 13

Answer

$\frac{1}{3}$

Work Step by Step

We know that $y=log_{b}x$ is equivalent to $b^{y}=x$ (where $x\gt0$, $b\gt0$, and $b\ne1$). Also, based on the definition of the common logarithm, we know that $log(x)=log_{10}x$. Therefore, $log\sqrt[3] 10=log_{10}\sqrt[3] 10=\frac{1}{3}$, because $10^{\frac{1}{3}}=\sqrt[3] 10$.
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