College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Mid-Chapter Check Point - Page 479: 25

Answer

$= \ln (\frac{\sqrt x}{y^{3}(z-2)})$

Work Step by Step

$= \frac{1}{2} \ln x - 3\ln y - \ln (z-2)$ $= \ln \sqrt x - \ln y^{3} - \ln (z-2)$ $= \ln \frac{\sqrt x}{y^{3}} - \ln (z-2)$ $= \ln (\frac{\sqrt x}{y^{3}(z-2)})$
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