College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 4 - Mid-Chapter Check Point - Page 479: 22

Answer

$= 19 + 20 \ln x$

Work Step by Step

$= \ln(e^{19}x^{20})$ $= \ln e^{19} + \ln x^{20}$ $= 19\ln e + 20\ln x$ $= 19 + 20 \ln x$
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