Answer
$x\ne-3,±1$
Work Step by Step
Set the denominator equal to zero to find the values that are not part of the domain. Then factor the terms by pulling out the greatest common factors. Then set the parentheses equal to zero to solve for $x$.
$x^3+3x^2-x-3=0$
$x^2(x+3)-1(x+3)=0$
$(x^2-1)(x+3)=0$
$x^2=1$
$x=±1$
$x+3=0$
$x=-3$
$x\ne-3,±1$
