College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 179: 83

Answer

Solution set as $x$-intercepts = $\{2,3\}$ The graph of equation $y=(x+2)^{2}-9(x+2)+20 $ is shown in Graph$(f)$

Work Step by Step

$y=(x+2)^{2}-9(x+2)+20 $ To find $x$ -intercept, $y=0$ $(x+2)^{2}-9(x+2)+20 =0$ Let $u= x+2$ $u^{2}-9u+20 =0$ By factoring, $(u-4)(u-5)=0$ $u=4$ or $u=5$ Let $u=4$ Replace $u$ with $x+2$ $x+2 = 4$ $x= 2$ Let $u=5$ $x+2 = 5$ $x=3$ Solution set as $x$-intercepts = $\{2,3\}$ The graph of equation $y=(x+2)^{2}-9(x+2)+20 $ is shown in Graph$(f)$
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