College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 179: 86

Answer

$x=5$ and $x=-\dfrac{11}{3}$ satisfy the given conditions

Work Step by Step

$y=|2-3x|$ and $y=13$ Substitute $y$ by $13$: $|2-3x|=13$ Solving an absolute value equation is equivalent to solving two separate equations, which are $2-3x=13$ and $2-3x=-13$ Solve these two equations for $x$: $2-3x=13$ $-3x=13-2$ $-3x=11$ $x=-\dfrac{11}{3}$ $2-3x=-13$ $-3x=-13-2$ $-3x=-15$ $x=\dfrac{-15}{-3}$ $x=5$ $x=5$ and $x=-\dfrac{11}{3}$ satisfy the given conditions
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