College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 179: 102

Answer

$A=4\pi r^{2}$

Work Step by Step

$r=\sqrt{\dfrac{A}{4\pi}}$ $;$ Solve for $A$ $r=\sqrt{\dfrac{A}{4\pi}}$ Square both sides of the equation: $r^{2}=\Big(\sqrt{\dfrac{A}{4\pi}}\Big)^{2}$ $r^{2}=\dfrac{A}{4\pi}$ Take $4\pi$ to multiply the left side: $4\pi r^{2}=A$ Rearrange: $A=4\pi r^{2}$
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