Answer
$x=30$ satisfies the given conditions
Work Step by Step
$y=(x-5)^{3/2}$ and $y=125$
Substitute $y$ by $125$:
$(x-5)^{3/2}=125$
Raise both sides of the equation to $\dfrac{2}{3}$:
$[(x-5)^{3/2}]^{2/3}=125^{2/3}$
$x-5=\sqrt[3]{125^{2}}$
$x-5=25$
Solve for $x$:
$x=25+5$
$x=30$
$x=30$ satisfies the given conditions
