College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 179: 101

Answer

$V=\dfrac{\pi hr^{2}}{3}$

Work Step by Step

$r=\sqrt{\dfrac{3V}{\pi h}}$ $;$ Solve for $V$: $r=\sqrt{\dfrac{3V}{\pi h}}$ Square both sides: $r^{2}=\Big(\sqrt{\dfrac{3V}{\pi h}}\Big)^{2}$ $r^{2}=\dfrac{3V}{\pi h}$ Take $\pi h$ to multiply the left side: $\pi hr^{2}=3V$ Take the $3$ to divide the left side: $\dfrac{\pi hr^{2}}{3}=V$ Rearrange: $V=\dfrac{\pi hr^{2}}{3}$
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