College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 179: 91

Answer

$x=0$ satisfies the given conditions.

Work Step by Step

$y=(x+4)^{3/2}$ and $y=8$ Substitute $y$ by $8$: $(x+4)^{3/2}=8$ Raise both sides to $\dfrac{2}{3}$: $[(x+4)^{3/2}]^{2/3}=8^{2/3}$ $x+4=\sqrt[3]{8^{2}}$ $x+4=4$ Solve for $x$: $x=4-4$ $x=0$ $x=0$ satisfies the given conditions.
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