College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.6 - Page 180: 105


$5.4$ feet

Work Step by Step

Plug the given time into the formula. Multiply the denominator on both sides, and then square both sides to get the vertical distance. $t=\frac{\sqrt d}{2}$ $1.16=\frac{\sqrt d}{2}$ $1.16*2=\sqrt d$ $2.32=\sqrt d$ $d\approx5.4$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.