## College Algebra (6th Edition)

$5.4$ feet
Plug the given time into the formula. Multiply the denominator on both sides, and then square both sides to get the vertical distance. $t=\frac{\sqrt d}{2}$ $1.16=\frac{\sqrt d}{2}$ $1.16*2=\sqrt d$ $2.32=\sqrt d$ $d\approx5.4$