Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 249: 37



Work Step by Step

Vertex: $(h,k)=(-2,5)$ Standard form: $y=a(x-h)^2+k$ $y=a[x-(-2)]^2+5$ $y=a(x+2)^2+5$ Now, use the point $(0,9)$ to find $a$: $9=a(0+2)^2+5$ $9-5=a(4)$ $a=\frac{4}{4}=1$ $y=(x+2)^2+5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.