Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 249: 56

Answer

According to the graph the x-intercepts are: $(3,0)$ and $(-15,0)$
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Work Step by Step

$f(x)=0$ $\frac{7}{10}(x^2+12x-45)=0~~$ (Divide both sides by $\frac{7}{10}$) $x^2+12x-45=0~~$ ($a=1,b=12,c=-45$): $x=\frac{-12±\sqrt {12^2-4(1)(-45)}}{2(1)}=\frac{-12±\sqrt {324}}{2}=\frac{-12±18}{2}=-6±9$ $x=3$ or $x=-15$ x-intercepts: $(3,0)$ and $(-15,0)$
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