Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 249: 53

Answer

According to the graph the x-intercepts are: $(3,0)$ and $(6,0)$
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Work Step by Step

$f(x)=0$ $x^2-9x+18=0~~$ ($a=1,b=-9,c=18$): $x=\frac{-(-9)±\sqrt {(-9)^2-4(1)(18)}}{2(1)}=\frac{9±\sqrt 9}{2}=\frac{9±3}{2}$ $x=6$ or $x=3$ x-intercepts: $(3,0)$ and $(6,0)$
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