Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 249: 46



Work Step by Step

Vertex: $(h,k)=(6,6)$ Standard form: $y=a(x−h)^2+k$ $y=a(x-6)^2+6$ Now, use the point $(\frac{61}{10},\frac{3}{2})$ to find $a$: $\frac{3}{2}=a(\frac{61}{10}-6)^2+6$ $\frac{3}{2}-6=a(\frac{1}{10})^2$ $-\frac{9}{2}=a(\frac{1}{100})$ $a=-\frac{900}{2}=-450$ $y=-450(x-6)^2+6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.