Algebra and Trigonometry 10th Edition

According to the graph the x-intercepts are: $(10,0)$ and $(-2,0)$
$f(x)=0$ $x^2-8x-20=0~~$ ($a=1,b=-8,c=-20$): $x=\frac{-(-8)±\sqrt {(-8)^2-4(1)(-20)}}{2(1)}=\frac{8±\sqrt {144}}{2}=\frac{8±12}{2}$ $x=10$ or $x=-2$ x-intercepts: $(10,0)$ and $(-2,0)$