Answer
Visually, the parabola intersects the x-axis in two points: $x=-1$ and $x=5$. The x-intercepts are: $(-1,0)$ and $(5,0)$
Algebraically: the x-intercepts are $(5,0)$ and $(-1,0)$
Work Step by Step
$f(x)=0$
$x^2-4x-5=0~~$ ($a=1,b=-4,c=-5$):
$x=\frac{-(-4)±\sqrt {(-4)^2-4(1)(-5)}}{2(1)}=\frac{4±\sqrt {36}}{2}=\frac{4±6}{2}=2±3$
$x=5$ or $x=-1$
x-intercepts: $(5,0)$ and $(-1,0)$
