Answer
$y=-\frac{1}{4}(x-2)^2+3$
Work Step by Step
Vertex: $(h,k)=(2,3)$
Standard form:
$y=a(x-h)^2+k$
$y=a(x-2)^2+3$
Now, use the point $(0,2)$ to find $a$:
$2=a(0-2)^2+3$
$2-3=a(4)$
$a=-\frac{1}{4}$
$y=-\frac{1}{4}(x-2)^2+3$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 249: 40
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