Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 249: 55

Answer

According to the graph the x-intercepts are: $(6,0)$ and $(-\frac{5}{2},0)$
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Work Step by Step

$f(x)=0$ $2x^2-7x-30=0~~$ ($a=2,b=-7,c=-30$): $x=\frac{-(-7)±\sqrt {(-7)^2-4(2)(-30)}}{2(2)}=\frac{7±\sqrt {289}}{4}=\frac{7±17}{4}$ $x=6$ or $x=-\frac{10}{4}=-\frac{5}{2}$ x-intercepts: $(6,0)$ and $(-\frac{5}{2},0)$
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