Answer
One that opens upwards:
$y=x^2-x-6$
One that opens downwards:
$y=-x^2+x+6$
Work Step by Step
Use:
$y=a(x-x_1)(x-x_2)$, where $x_1$ and $x_2$ are the $x$ of the x-intercepts.
$y=a[x-(-2)](x-3)=a(x^2-3x+2x-6)=a(x^2-x-6)$
One that opens upwards ($a\gt0$).
$y=1(x^2-x-6)=x^2-x-6$
One that opens downwards ($a\lt0$).
$y=-1(x^2-x-6)=-x^2+x+6$