Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 249: 42



Work Step by Step

Vertex: $(h,k)=(-2,-2)$ Standard form: $y=a(x-h)^2+k$ $y=a[x-(-2)]^2+(-2)$ $y=a(x+2)^2-2$ Now, use the point $(-1,0)$ to find $a$: $0=a(-1+2)^2-2$ $2=a(1)$ $a=2$ $y=2(x+2)^2-2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.