Answer
$y=-2(x+2)^2+2$
Work Step by Step
Vertex: $(h,k)=(-2,2)$
Standard form:
$y=a(x-h)^2+k$
$y=a[x-(-2)]^2+2$
$y=a(x+2)^2+2$
Now, use the point $(-1,0)$ to find $a$:
$0=a(-1+2)^2+2$
$-2=a(1)$
$a=-2$
$y=-2(x+2)^2+2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 248: 36
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