Work Step by Step
Vertex: $(h,k)=(-2,2)$ Standard form: $y=a(x-h)^2+k$ $y=a[x-(-2)]^2+2$ $y=a(x+2)^2+2$ Now, use the point $(-1,0)$ to find $a$: $0=a(-1+2)^2+2$ $-2=a(1)$ $a=-2$ $y=-2(x+2)^2+2$
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