Work Step by Step
Vertex: $(h,k)=(-2,-1)$ Standard form: $y=a(x-h)^2+k$ $y=a[x-(-2)]^2+(-1)$ $y=a(x+2)^2-1$ Now, use the point $(0,3)$ to find $a$: $3=a(0+2)^2-1$ $3+1=a(4)$ $a=1$ $y=(x+2)^2-1$
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