Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 88

Answer

$\displaystyle \sum_{j=1}^{6}\frac{i!}{2^i}$

Work Step by Step

$\frac{1}{2}+\frac{2}{4}+\frac{6}{8}+\frac{24}{16}+\frac{120}{32}+\frac{720}{64}=\frac{1!}{2^1}+\frac{2!}{2^2}+\frac{3!}{2^3}+\frac{4!}{2^4}+\frac{5!}{2^5}+\frac{6!}{2^6}=\displaystyle \sum_{j=1}^{6}\frac{i!}{2^i}$
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