Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 87


$\displaystyle \sum_{i=1}^{5}\frac{2^i-1}{2^{i+1}}$

Work Step by Step

$\frac{1}{4}+\frac{3}{8}+\frac{7}{16}+\frac{15}{32}+\frac{31}{64}=\frac{2^1-1}{2^{1+1}}+\frac{2^2-1}{2^{2+1}}+\frac{2^3-1}{2^{3+1}}+\frac{2^4-1}{2^{4+1}}+\frac{2^5-1}{2^{5+1}}=\displaystyle \sum_{i=1}^{5}\frac{2^i-1}{2^{i+1}}$
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