Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 778: 70


$\displaystyle \sum_{i=1}^{5}(2i-1)=25$

Work Step by Step

$\displaystyle \sum_{i=1}^{5}(2i-1)=(2(1)-1)+(2(2)-1)+(2(3)-1)+(2(4)-1)+(2(5)-1)=1+3+5+7+9=25$
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